x-2=(2x-5)^1/2

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Solution for x-2=(2x-5)^1/2 equation: 


x in (-oo:+oo)

x-2 = ((2*x-5)^1)/2 // - ((2*x-5)^1)/2

x-(((2*x-5)^1)/2)-2 = 0

x-((2*x-5)/2)-2 = 0

(-1*(2*x-5))/2+x-2 = 0

(-1*(2*x-5))/2+(2*x)/2+(-2*2)/2 = 0

2*x-1*(2*x-5)-2*2 = 0

5-4 = 0

1 = 0

1/2 = 0

1/2 = 0 // * 2

1 = 0

x belongs to the empty set

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